All Important Formula — Class 11 Physics Notes
All Important Formula · Class 11 Physics · 4 topics.
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Topics covered in All Important Formula
1.Optics
1. Snell's Law for Refractive Index
μ1μ2=sinisinr
Example:
A light ray travels from air (μ1=1) to water (μ2=1.33). If the angle of incidence i is 30∘, find the angle of refraction r.
Solution:11.33=sin30∘sinr
0.752=0.5sinr
sinr=0.50.752=0.665
r=sin−1(0.665)≈41.8∘2. Brewster's Law
μ=tanp(p = Angle of polarization)
Example:If the angle of polarization p is 56∘, find the refractive index μ.
Solution:μ=tan56∘≈1.48
3. Relation Between Refractive Indices
n12×n21=1
n21=1n12Example:
If n12=1.5, find n21.
Solution:n21=11.5=0.67
4. Refractive Index Formula
μ=sinisinr
Example:
A light ray travels from air to glass with an incidence angle of 45∘ and a refraction angle of 28∘. Find the refractive index of glass.
Solution:μ=sin45∘sin28∘=0.7070.469≈1.51
5. Mirror Formula
1f=1v+1u
Example:
An object is placed 20 cm in front of a concave mirror with a focal length of 10 cm. Find the image distance v.
Solution:1−10=1v+1−20
1v=1−10+120=−2+120=−120
v=−20 cm6. Lens Maker Formula
In a Medium:
1f=(μ−1)(1R1−1R2)In Air:
1f=(μ−1)(1R1−1R2)
Example:
For a lens with μ=1.5, R1=20 cm and R2=−30 cm, find the focal length f.
Solution:1f=(1.5−1)(120−1−30)
1f=0.5(120+130)
1f=0.5(3+260)=0.5×560=5120
f=24 cm7. Equivalent Focal Length for Two Focal Lengths f1 and f2
1F=1f1+1f2
Example:
Two lenses have focal lengths f1=10 cm and f2=20 cm. Find the equivalent focal length F.
Solution:1F=110+120=2+120=320
F=203≈6.67 cm8. Power of a Lens
P=100f(in cm)
Example:
If the focal length of a lens is 25 cm, find its power.
Solution:
P=10025=4 diopters
9. Refraction Through Prism
μ=sin(A+Dm2)sin(A2)
Example:
If the refractive angle A=60∘ and the angle of minimum deviation Dm=40∘, find the refractive index μ.
Solution:μ=sin(60∘+40∘2)sin(60∘2)μ=sin50∘sin30∘μ=0.7660.5=1.532
2.Oscillation Formulas
1. Differential Equation for SHM
d2xdt2+ω2x=0
Explanation:
This represents the equation of simple harmonic motion (SHM).
Example:If ω=3 rad/s, the equation becomes:
d2xdt2+32x=0ord2xdt2+9x=0
2. Velocity in SHM
V=±ωA2−x2
Explanation:
This gives the velocity at a displacement x.
Example:If ω=4 rad/s, A=5 m, and x=3 m:
V=±452−32=±425−9=±416=±16 m/s
3. Maximum Velocity (Vmax)
Vmax=ωA
Explanation:This is the highest velocity the particle achieves.
Example:If ω=6 rad/s and A=2 m:
Vmax=6×2=12 m/s
4. Acceleration in SHM
a=−ω2x
Explanation:
The acceleration is proportional to the displacement but in the opposite direction.
Example:If ω=5 rad/s and x=2 m:
a=−52×2=−25×2=−50 m/s2
5. Displacement in SHM
x=Asin(ωt±ϕ)
Explanation:
The position of the particle as a function of time.
Example:If A=3 m, ω=2 rad/s, and ϕ=0, at t=1 s:
x=3sin(2×1)=3sin2≈3×0.909=2.727 m
6. Time Period for SHM
T=2πω
Explanation:
Time for one complete oscillation.
Example:If ω=2 rad/s:
T=2π2=π≈3.14 s
7. Angular Frequency (ω)
ω=2πT
Example:
If T=4 s:
ω=2π4=π2≈1.57 rad/s
8. Potential Energy (P.E.)
P.E.=12mω2x2=12kx2
Example:
If m=1 kg, ω=3 rad/s, and x=2 m:
P.E.=12×1×32×22=12×9×4=18 J
9. Kinetic Energy (K.E.)
K.E.=12mω2(A2−x2)
Example:
If m=2 kg, ω=4 rad/s, A=3 m, x=1 m:
K.E.=12×2×42×(32−12)=1×16×(9−1)=128 J
10. Total Energy (T.E.)
T.E.=12mω2A2=12kA2
Example:
If m=1 kg, ω=5 rad/s, and A=2 m:
T.E.=12×1×52×22=12×25×4=50 J
11. Time Period of a Simple Pendulum
T=2πlg
Example:
If l=1 m and g=9.8 m/s2:
T=2π19.8≈2π×0.319=2.006 s
12. Time Period for a Mass-Spring System
T=2πmk
Example:
If m=2 kg and k=8 N/m:
T=2π28=2π0.25=2π×0.5≈3.14 s
13. Frequency (f)
f=1T
Example:
If T=2 s:
f=12=0.5 Hz
3.Gravitation Formulas and Constant Values of Physical Quantities
Gravitation Formulas
1. Newton’s Law of Gravitation
F=GMmr2
Explanation:
The gravitational force between two masses M and m separated by distance r.
F=6.67×10−11×10×522=6.67×10−11×504=8.34×10−10 N
Example:
If M=10 kg, m=5 kg, r=2 m, and G=6.67×10−11 Nm2/kg2:
2. Gravitational Constant
G=6.67×10−11 Nm2/kg2
- Explanation:
Universal constant used in the calculation of gravitational force.
3. Acceleration Due to Gravity (g)
g=GMR2
Explanation:
The acceleration due to gravity on the surface of a planet of mass M and radius R.Example:
g=6.67×10−11×5.98×1024(6.37×106)2≈9.8 m/s2
If M=5.98×1024 kg and R=6.37×106 m:
4. Gravitational Potential Energy
U=−GMmr
Explanation:
The potential energy between two masses M and m separated by distance r.Example:
U=−6.67×10−11×10×52=−1.67×10−9 J
If M=10 kg, m=5 kg, r=2 m:
5. Orbital Velocity (v0)
v0=GMr
Explanation:
The velocity required to keep a body in a circular orbit around a planet.Example:
v0=6.67×10−11×5.98×10246.37×106≈7.9 km/s
If M=5.98×1024 kg and r=6.37×106 m:
6. Escape Velocity (ve)
ve=2GMR
Explanation:
The minimum velocity needed to escape the gravitational pull of a planet.Example:
ve=2×6.67×10−11×5.98×10246.37×106≈11.2 km/s
For Earth, if M=5.98×1024 kg and R=6.37×106 m:
7. Time Period of a Satellite (T)
T=2πr3GM
- Explanation:
The time taken for one complete revolution of a satellite around a planet.
8. Kepler’s Third Law
T2∝r3
- Explanation:
The square of the time period of a planet’s orbit is proportional to the cube of the semi-major axis of the orbit.
9. Weight on a Planet (W)
W=mg
- Explanation:
The weight of an object is the force due to gravity acting on it.
Constant Values of Physical Quantities
Velocity of Light (c)
3×108 m/sGravitational Constant (G)
6.67×10−11 Nm2/kg
2Acceleration Due to Gravity on Earth (g)
9.8 m/s
2Planck’s Constant (h)
6.63×10−34 JsAvogadro’s Number (NA)
6.022×1023 mol
−1Boltzmann Constant (k)
1.38×10−23 J/KUniversal Gas Constant (R)
8.314 J/mol\KElectron Charge (e)
1.6×10−19 CMass of Electron
9.11×10−31 kgMass of Proton
1.67×10−27 kgPermittivity of Free Space (ϵ0)
8.85×10−12 C2/Nm2Permeability of Free Space (μ0)
4π×10−7 Tm/AStefan-Boltzmann Constant (σ)
5.67×10−8 W/m2K4Gas Density of Air
1.29 kg/m3Speed of Sound in Air
343 m/s
4.Electromagnetic Induction Formula
1. Faraday's Law of Induction
Formula:
ε=−dϕdt
Explanation:
The induced EMF (ε) is proportional to the rate of change of magnetic flux (ϕ) through a circuit. The negative sign follows Lenz's Law.
Example:
If the magnetic flux changes by 0.2 Wb in 0.1 s, the induced EMF is:
ε=−0.20.1=−2 V2. Magnetic Flux
Formula:
ϕ=B⋅A⋅cosθExplanation:
Magnetic flux (ϕ) depends on the magnetic field (B), area (A), and the angle (θ) between the field lines and the normal to the surface.
Example:
If B=5 T, A=0.1 m2, and θ=30∘:
ϕ=5×0.1×cos30∘=0.5×0.866=0.433 Wb3. Induced EMF in a Loop
Formula:
ε=−Ndϕdt
Explanation:
If a coil with N turns experiences a changing magnetic flux, the induced EMF is proportional to N and the rate of change of flux.4. Induced EMF for a Moving Conductor
Formula:
ε=Bℓvsinθ
Explanation:
The EMF induced in a conductor of length ℓ moving with velocity v through a magnetic field B.
Example:
If B=2 T, ℓ=0.5 m, v=3 m/s, and θ=90∘:
ε=2×0.5×3=3 V5. Lenz's Law
Formula:
ε=−dϕdt
Explanation:
The induced EMF opposes the change in magnetic flux that caused it.6. Self-Inductance (L)
Formula:
L=NϕI
Explanation:
Self-inductance (L) is the ratio of the magnetic flux (ϕ) linked with the coil to the current (I) producing it.7. Induced EMF due to Self-Inductance
Formula:
ε=−LdIdt
Explanation:
The EMF induced due to a changing current in the same coil.8. Energy Stored in an Inductor
Formula:
U=12LI2
Explanation:
The energy stored in an inductor due to the current I flowing through it.9. Mutual Inductance (M)
Formula:
M=N2ϕ21I1
Explanation:
Mutual inductance (M) is the ratio of the magnetic flux linked with the second coil to the current in the first coil.10. Induced EMF due to Mutual Inductance
Formula:
ε2=−MdI1dt
Explanation:
The EMF induced in one coil due to a changing current in another coil.11. Angular Frequency (ω)
Formula:
ω=2πf
Explanation:
Angular frequency ω is related to frequency f.12. Power in AC Circuit
Formula:
P=VIcosϕ
Explanation:
Power (P) in an AC circuit depends on voltage (V), current (I), and phase angle (ϕ).13. Impedance in Series R-L Circuit
Formula:
Z=R2+(ωL)2
Explanation:
Impedance (Z) of a series circuit with resistance (R) and inductance (L).14. Resonant Frequency
Formula:
f0=12πLC
Explanation:
The frequency at which a circuit naturally oscillates.